Question

urrently quarters have weights that are normally distributed with a mean of 5.670 g and a standard deviation of 0.062 g a vending machine is configured to accept only those quarters with weights between 5.550g if 280 diffferent quarters are inserted into the vending machine what is the probability that the mean falls between the limits of 5.550g and 5.790g
a. 0.0002
b.0.9476
c.0.9998
d.0.0524

Answer 1

Answer: B) .9476

Step-by-step explanation

Its easiest to solve on a TI calculator.

1. Identify your mean, standard deviation, and your lower/high limits. (Lower = 5.550 Higher = 5.790)

2. Now use calculator..

2nd>vars>normalcdf

Fill it in with your data then click paste.

(IF YOU HAVE TO SHOW YOUR WORK WRITE OUT WHATS GIVEN ON YOUR CALC..  normalcdf(5.550,5.790,5.670,.062) )

= .9470691924

Rounded to four decimals..

Answer 2

Answer:

The correct answer is C. 0.9998

Step-by-step explanation:

grad point verified