Question

A monatomic ideal gas is compressed at a constant pressure of 0.293 atm from a volume of 8.26 L to 3.32 L. In the process, heat energy flows out of the gas. What is the work done on the gas?

Answer 1

The work done on the gas as it is compressed from volume 1 to volume 2 is 146.7 J.

Given the data in the question;

• Pressure; $P = 0.293 atm = 29688.225pa$

• Initial volume; $v_1 = 8.26L = 0.00826m^3$

• Final volume; $v_2 = 3.32L = 0.00332m^3$

Work done on the gas; $W = \ ?$

From the first law of thermodynamic:

$W = -P\delta v$

Where W is work done, P is pressure and $\delta v$ is  change in volume.

We substitute our values into the equation

$W = -29688Pa * ( 0.00332m^3- 0.00826m^3)\\\\W = -29688Pa * -0.00494m^3\\\\W= 146.7 J$

Therefore, the work done on the gas as it is compressed from volume 1 to volume 2 is 146.7 J.

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