The prism below has two faces that are regular hexagons. Each hexagonal face has an area of 42 cm^2. What is the surface area of the prism? Remember to give the correct units. Not drawn accurately​

The prism below has two faces that are regular hexagons Each hexagonal face has an area of 42 cm2 What is the surface area of the prism Remember to give the cor class=

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Answer:  276 cm^2

Explanation:

The hexagonal faces are the bases of the prism. They account for 2*42 = 84 sq cm of surface area so far.

The lateral faces are the rectangles that make up the side walls of this building (think of the bases as the floor and ceiling). Each rectangular wall has area of 8*4 = 32 cm^2. Having 6 of these walls gives us a lateral surface area of 6*32 = 192 cm^2. Add this onto the 84 we calculated earlier to get 192+84 = 276 cm^2

Here's one way to write out the arithmetic expression in one single line

surface area = 2*42 + 6*8*4 = 276

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