Answer:
6.44 Kgm
Explanation:
How many grams of dichloromethane result from reaction of 2.52 kg of methane if the yield is 48.0 % ?
CH4 (g) + 2Cl2 (g) → CH2Cl2 (1) + 2HCl(9)
methane CH4 has a molar mass of 12 +4X1 =16
2.52 kg = 2520 gm of methane
2520/16 = 158 moles of methane
48.0% is converted to dichlroromethane
0.480 X 158 moles =75.8 moles of dichloromethane ..CH2Cl2
CH2Cl2 molar mass id 12 +2X1+ 35.45 X2 =12 + 2 + 70.9=84.9 gm/mole
so 75.8 moles = 75.8 X 84.9 = 6440 gm (TO CORRECT SIG FIG) =
6.44 Kgm
