Question

Write an equation in point slope form for the line through the given point with the given slope (4,-6); m=3/5

Answer 1

$The\ point-slope\ form:y-y_1=m(x-x_1)\\---------------------\\m=\frac{3}{5}\\\\(4;-6)\to x_1=4\ and\ y_1=-6\\\\subtitute:\\\\y-(-6)=\frac{3}{5}(x-4)\\\\\boxed{y+6=\frac{3}{5}(x-4)}$

Answer 2

y - y₁ = m(x - x₁)
y - (-6) = 3/5(x - 4)
y + 6 = 3/5(x) - 3/5(4)
y + 6 = 3/5x - 2 2/5
     -6              -6     
      y = 3/5x - 8 2/5