Question

A bicycle takes 8.0 seconds to accelerate at a constant rate from rest to a speed of 4.0 m/s. If the mass of the bicycle and rider together is 85 kg, what is the net force acting on the bicycle? (Hint: first, calculate acceleration) Acceleration = Fnet =​

Answer 1

Answer:

42.5km/s^2

Explanation:

Fnet=m⋅a

We know that

$a=\frac{v-u}{t}$

Here,  

v=4m/s,  u=0m/s,  t=8s

 

$a=\frac{4m/s-0m/s}{8s} =0/5m/s^2$

Also, we have  m=85kg

Fnet=85  kg⋅0.5  m/s2=42.5N

Acceleration = (change in speed) / (time for the change)

Acceleration = (4 m/s) / (8 seconds)

Acceleration = 0.5 m/s²

Force = (mass) x (acceleration)

Force = (85 kg) x (0.5 m/s²)

Force = 42.5 Newtons

Answer 2

Answer:

$\sf\longmapsto42.5 N$

Explanation:

We would need to use Newton's second law ofmotion, which states that-

$\sf \longmapsto \: F _{net} = m•a$

We know that,

$\sf \longmapsto \: a = \frac{v - u}{t}$

Here,v = 4 m/s, u = 0 m/s, t = 8 s

$\sf \longmapsto \: a = \frac{4 \: m/s - 0 \: m/s}{8s} = 0.5 \: m / {s}^{2}$

Also, we have

m = 85 kg

$\sf \longmapsto \: F _{net} = 85 \: kg \: • \: 0.5 m / {s}^{2} \: \: = 42.5 \: N$