Question

How do I solve for x? X+6x=56

Answer 1

$ax^2+bx+c=0$
$x^2+6x=56$
$x^2+6x-56=0$
a=1    b=6    c=-56
$\Delta=b^2-4ac=6^2-4*1(-56)=36+224=260$
$\sqrt{\Delta}=2\sqrt{65}$
$x_1=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-6-2\sqrt{65}}{2*1}=-3-\sqrt{65}$
$x_2=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-6+2\sqrt{65}}{2*1}=-3+\sqrt{65}$

Answer 2

x+6x=56

7x=56

x= 8

So, x is equal to 8