Respuesta :

Answer:

[tex]{ \rm{4x - 3y = 12 - - - \{eqn(a) \}}} \\ { \rm{4x - 5y = - 4 - - - \{eqn(b) \}}}[/tex]

• subtract eqn(b) from eqn(a);

[tex]{ \underline{ \rm{ - \binom{4x - 3y = 12}{4x - 5y = - 4} }}} \\ { \rm{0x + 2y = 16}} \\ \\ { \rm{2y = 16}} \\ \\ { \boxed{ \tt{ \: \: y = 8 \: \: }}} \\ [/tex]

• find x :

[tex]{ \rm{4x - 3y = 12}} \\ { \rm{4x - 3(8) = 12}} \\ { \rm{4x = 36}} \\ \\ { \boxed{ \tt{ \: \: x = 9 \: \: }}}[/tex]

I think the answers is

Y=8
X=9
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