Respuesta :
Answer:
[tex]{ \rm{4x - 3y = 12 - - - \{eqn(a) \}}} \\ { \rm{4x - 5y = - 4 - - - \{eqn(b) \}}}[/tex]
• subtract eqn(b) from eqn(a);
[tex]{ \underline{ \rm{ - \binom{4x - 3y = 12}{4x - 5y = - 4} }}} \\ { \rm{0x + 2y = 16}} \\ \\ { \rm{2y = 16}} \\ \\ { \boxed{ \tt{ \: \: y = 8 \: \: }}} \\ [/tex]
• find x :
[tex]{ \rm{4x - 3y = 12}} \\ { \rm{4x - 3(8) = 12}} \\ { \rm{4x = 36}} \\ \\ { \boxed{ \tt{ \: \: x = 9 \: \: }}}[/tex]