Question

(b) Photoelectron spectroscopy data for the 1s sublevel of Se and the 1s sublevel of Po are represented below. In
terms of Coulomb's law and atomic structure, explain why the peak for Po is positioned so far to the left of the
peak for Se.
Relative Number
of Electrons
Se
CH
10,000
2000
8000 6000 4000
Binding Energy (MJ/mol)
on
sen
Relative Number
of Electrons
Ро
10,000
8000 6000 4000
Binding Energy (MJ/mol)
2000

Answer 1

The peak for Po is positioned so far to the left of the  peak for Se because the 1s electrons in Po are closer to the the nucleus compared to the 1s electrons in Se.

In photoelectron spectroscopy, energy is imparted to an electron in an atom and its binding energy is determined by the energy of ultraviolet radiation required to ionize it.

The energy required to ionize an electron in an atom depends on its binding energy. We must note that the 1s electrons are closer to the nucleus.

The 1s electrons in Po are more closely held to the nucleus than the 1s electrons in Se thus there is greater Coulombic attraction between the 1s electrons in Po and the nucleus compared to the 1s electrons in Se. Hence, the peak for Po is positioned so far to the left of the  peak for Se.

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