Question

Iron has a density of 11.6 g/cm3. What is the mass (in g) of a cube of iron with the length of one side equal to 5.7 mm?

Answer 1

The mass of cube of Iron will be "2.15 g".

Given:

• Density = 11.6 g/cm³
• Length of side of cube = 5.7 mm or 0.57 mm

→ Volume of cube will be:

= $(0.57)^3 \ cm^3$

= $0.185 \ cm^3$                

As we know,

→ $Density = \frac{Mass}{Volume}$

or,

→ $Mass = Density\times Volume$

By substituting the values, we get

→           $= 11.6\times 0.185$

→           $= 2.15 \ g$

Thus the above solution is right.                        

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