Question

A certain triathlon consists of a 2.2 mile swim, a 108 mile bicycle ride, and a 25.4 mile run. At one point, a participant had completed twice as many miles as the number of miles left to complete. How many miles had he completed at that mark?

Answer 1

Answer:

He had completed at that mark  90.4 miles

Step-by-step explanation:

step 1

Find the total miles of the triathlon

we have

swim ----> 2.2 mi

bicycle ---> 108 mi  

run ----> 25.4 mi

Adds the number of miles

$2.2+108+25.4=135.6\ mi$

step 2

Find out how many miles he had completed at that mark

Let

x ---->  the number of miles left to complete

we know that

At one point a participant had completed 135.6-x

At one point, a participant had completed twice as many miles as the number of miles left to complete

so

$(135.6-x)=2x$

solve for x

$2x+x=135.6\\3x=135.6\\x=45.2\ mi$

He had completed at that mark

$2(45.2)=90.4\ mi$