Question

What pressure will be exerted by 0.57 moles of CO, at a temperature of 298 K and a volume of 500ml?

Answer 1

Answer:

28atm

Explanation:

pv=nrt

p(0.500L)=(0.57mols)(0.08206 L * atm/ K mol)(298K)

p=(0.57mols)(0.08206 L * atm/ K mol)(298K)/(0.5L)

Just plug in numbers

27.8774232 ~ 28atm (2sig fig)