Answer:
Option: a is the correct answer.
a) Number line with numbers negative 4, negative 3, negative 2, negative 1, 0, 1, 2, 3, 4 labeled. A dot is made at 1.7 and labeled as square root of 3.
Step-by-step explanation:
We are asked to locate √3 in a number line.
We know that:
[tex]\sqrt{1}<\sqrt{3}<\sqrt{4}[/tex]
i.e.
[tex]1<\sqrt{3}<2[/tex]
i.e. the value of √3 lie between 1 and 2 in the number line.
b)
Number line with numbers negative 4, negative 3, negative 2, negative 1, 0, 1, 2, 3, 4 labeled. A dot is made at 2.8 and labeled as square root of 3.
As the value of square root of 3 has to be strictly less than 2.
Hence, option: b is incorrect.
(Since here we are given value strictly greater than 2 i.e. 2.8 )
c)
Number line with numbers negative 4, negative 3, negative 2, negative 1, 0, 1, 2, 3, 4 labeled. A dot is made at 3 and labeled as square root of 3.
Hence, option: c is incorrect.
(Since here we are given value strictly greater than 2 i.e. 3 )
d)
Number line with numbers negative 4, negative 3, negative 2, negative 1, 0, 1, 2, 3, 4 labeled. A dot is made at 2.2 and labeled as square root of 3.\
Hence, option: d is incorrect.
(Since here we are given value strictly greater than 2 i.e. 2.2 )
a)
Number line with numbers negative 4, negative 3, negative 2, negative 1, 0, 1, 2, 3, 4 labeled. A dot is made at 1.7 and labeled as square root of 3.
Hence, option: a is correct.
( Since the value given lie between 1 and 2 i.e. 1.7 )
