Answer:
z<-2 or z<1
Step-by-step explanation:
The compound inequality to be solved is
5z+3<-7 or -2z-6>-8
[tex] \implies \:5z<-7 - 3 \: or -2z>-8 + 6[/tex]
[tex]\implies \:5z<-10 \: or -2z>-2[/tex]
[tex]\implies \: \frac{5z}{5} < \frac{ - 10}{5} \: or \frac{-2z}{-2} > \frac{ - 2}{ - 2} [/tex]
Simplifying we get,
z<-2 or z<1
NB: the inequality sign at the right side of or has changed because we have divided through by -2