Answer:
0.84 s
Explanation:
Step 1
Given information:
Mass of the ice (m) = 2.0 kg
Heat transfer rate (Q/T) = 793.0 kW
Latent heat of fusion of ice (Lf) = 334 kJ/kg
[tex] \frac{Q}{T} = \frac{mLf}{T} [/tex]
Substituting the corresponding values we have:
[tex]793.0 kW= \frac{2.0kg(334 kJ/kg)}{T} \\ T = \frac{2.0kg(334 kJ/kg)}{793.0kW} = \frac{668kJ}{793kW} \\ = 0.84s[/tex]