25 POINTS HELP ME ASAPPPPPPPPPPPPPPPP!!!!!!

Answer:
1/6?
Let's do it...
( (3^(3/4))/(3^(3/8)) )^4/9
According to indices rules here the denominator and numerator has the same base and they are dividing so the powers will subtract..... Its just a formulae not rocket science so don't freak out.
So ( 3^(3/4 - 3/8)) ^4/9
= ( 3^(3/8)) ^4/9
Again with indices rule the powers will multiply
Which will return us 3^1/6 which corresponds 3^x..... Hence x =1/6
Thank you
[tex] \boxed{ \boxed{x = \frac{1}{6} }}[/tex]
[tex] \hookrightarrow \: {\bigg( \dfrac{3 {}^{ \frac{3}{4} } }{ {3}^{ \frac{3}{8} } } \bigg) }^{ \frac{4}{9} } [/tex]
[tex] \hookrightarrow \: {(3 {}^{ \frac{3}{4} } \div 3 {}^{ \frac{3}{8} } ) } ^{ \frac{4}{9} } [/tex]
[tex] \hookrightarrow \: {(3 {}^{ \frac{3}{4} - \frac{3}{8} } ) }^{ \frac{4}{9} } [/tex]
[tex] \hookrightarrow \:{ (3 {}^{ \frac{3}{8} } ) }^{ \frac{4}{9} } [/tex]
[tex] \hookrightarrow \: 3 {}^{ \frac{3}{8} \times \frac{4}{9} } [/tex]
[tex] \hookrightarrow \: {3}^{ \frac{1}{6} } [/tex]
therefore,
the required value of x is 1/6