Correct Ans:
Option D
Solution.
This is a problem of statistics and uses the concepts of normal distribution. First step is to convert the given score into z score. 80 converted to z score for given mean, sample size and standard deviation will be:
[tex]z= \frac{80-83.6}{ \frac{8.7}{18} } =-1.756[/tex]
We are to find the probability that the class average is less than 80. Or in terms of z score, we have to find the score is less than -1.756.
Using the standard normal distribution table this probability comes out to be 0.0396.
Therefore, the probability that the class average is less than 80 is 0.0396