Both triangles have an area of 100 square centimeters and the area of the blue triangle showing is 51 square centimeters.
Based on the information given from statement, we can determine the missing length of the yellow triangle by means of simmilarity ratios, that is:
[tex]\frac{3\,cm}{6\,cm} = \frac{10\,cm}{x}[/tex] (1)
Where [tex]x[/tex] is the base of the yellow triangle, in centimeters.
Now we proceed to find the length base:
[tex]x = \frac{6\,cm}{3\,cm}\times 10\,cm[/tex]
[tex]x = 20\,cm[/tex]
The area of the triangle can be found by means of the following expression:
[tex]A = \frac{1}{2}\cdot b\cdot h[/tex] (2)
Where:
- [tex]A[/tex] - Area of the yellow triangle, in square centimeters.
- [tex]b[/tex] - Base, in centimeters.
- [tex]h[/tex] - Height, in centimeters.
If we know that [tex]b = 20\,cm[/tex] and [tex]h = 10\,cm[/tex], then the area of the triangle is:
[tex]A = \frac{1}{2}\cdot (20\,cm)\cdot (10\,cm)[/tex]
[tex]A = 100\,cm^{2}[/tex]
The area of the yellow triangle is 100 square centimeters and the area of the blue triangle is also 100 square centimeters due to congruency. The dimensions of the section of the yellow triangle overlapping the blue triangle are [tex]b = 14\,cm[/tex] and [tex]h = 7\,cm[/tex]. The area of this section is:
[tex]A' = \frac{1}{2}\cdot (14\,cm)\cdot (7\,cm)[/tex]
[tex]A' = 49\,cm^{2}[/tex]
And the area of the rest of the blue triangle is:
[tex]A'' = A - A'[/tex] (2)
[tex]A'' = 100\,cm^{2}-49\,cm^{2}[/tex]
[tex]A'' = 51\,cm^{2}[/tex]
In a nutshell, both triangles have an area of 100 square centimeters and the area of the blue triangle showing is 51 square centimeters.
We kindly invite to check this question on triangles: https://brainly.com/question/23103213