Write the equation of the line in fully simplified slope-intercept form.
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Answer:
[tex]y=-6x+2[/tex]
Step-by-step explanation:
Hi there!
Slope-intercept form: [tex]y=mx+b[/tex] where m is the slope and b is the y-intercept (the value of y when x=0)
1) Determine the slope (m)
[tex]m=\displaystyle \frac{y_2-y_1}{x_2-x_1}[/tex] where two points that fall on the line are [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex]
Given the graph, we determine which points we could use. For example, we could use the two points [tex](0,2)[/tex] and [tex](1,-4)[/tex]:
[tex]m=\displaystyle \frac{-4-2}{1-0}\\\\m=\displaystyle \frac{-6}{1}\\\\m=-6[/tex]
Therefore, the slope of the line is -6. Plug this into [tex]y=mx+b[/tex]:
[tex]y=-6x+b[/tex]
2) Determine the y-intercept (b)
Recall that the y-intercept occurs when x=0. Given the point (0,2), we know that the y-intercept is 2. Plug this into [tex]y=-6x+b[/tex]:
[tex]y=-6x+2[/tex]
I hope this helps!