Respuesta :

Answer:

[tex]y=-6x+2[/tex]

Step-by-step explanation:

Hi there!

Slope-intercept form: [tex]y=mx+b[/tex] where m is the slope and b is the y-intercept (the value of y when x=0)

1) Determine the slope (m)

[tex]m=\displaystyle \frac{y_2-y_1}{x_2-x_1}[/tex] where two points that fall on the line are [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex]

Given the graph, we determine which points we could use. For example, we could use the two points [tex](0,2)[/tex] and [tex](1,-4)[/tex]:

[tex]m=\displaystyle \frac{-4-2}{1-0}\\\\m=\displaystyle \frac{-6}{1}\\\\m=-6[/tex]

Therefore, the slope of the line is -6. Plug this into [tex]y=mx+b[/tex]:

[tex]y=-6x+b[/tex]

2) Determine the y-intercept (b)

Recall that the y-intercept occurs when x=0. Given the point (0,2), we know that the y-intercept is 2. Plug this into [tex]y=-6x+b[/tex]:

[tex]y=-6x+2[/tex]

I hope this helps!

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