Average speed is difined as the total distance travelled divided by the total time required to cover the distance. Mathematically, it is expressed as:
[tex]Ave. Speed = \frac{Total distance }{Total time}[/tex]
To obtain the average speed of Daniel, we shall determine the distance travelled in each case. This is illustrated below:
Speed 1 (S₁) = 6 mph
Time 1 (t₁) = 0.8 h.
[tex]Speed = \frac{Distance}{Time} \\\\S_{1} = \frac{D_{1}}{t_{1}} \\\\6 = \frac{D_{1}}{0.8}[/tex]
Cross multiply
D₁ = 6 × 0.8
Speed 2 (S₂) = 2 mph
Time 2 (t₂) = 1.2 h.
[tex]S_{2} = \frac{D_{2}}{t_{2}}\\\\2 = \frac{D_{2}}{1.2}[/tex]
Cross multiply
D₂ = 2 × 1.2
Next, we shall determine the total time. This can be obtained as follow:
Time 1 (t₁) = 0.8 h.
Time 2 (t₂) = 1.2 h.
T = t₁ + t₂
T = 0.8 + 1.2
Next, we shall determine the total distance. This can be obtained as follow:
Distance 1 (D₁) = 4.8 mile
Distance 2 (D₂) = 2.4 mile
D = D₁ + D₂
D = 4.8 + 2.4
Finally, we shall determine the average speed of Daniel. This can be obtained as follow:
Total time = 2 h
Total distance = 7.2 mile
[tex]Ave. speed = \frac{Total distance }{Total time} \\\\Ave. speed = \frac{7.2 }{2}[/tex]
Therefore, the average speed of Daniel is 3.6 mph
Learn more: https://brainly.com/question/680492