Question

What are the coordinates of the vertex of the function f(x)=x2+10x-3?
(-5, -28)
(-5, 28)
(5,-28)
(5, 28)

Answer 1

Answer:

(-5, -28)

Step-by-step explanation:

$f(x) = {x}^{2} + 10x - 3$

$= f(x) = {1x}^{2} + 10x - 3$

= a = 1, b = 10

$= x = \frac{10}{2 \times 1}$

$= x = - \frac{10}{2}$

= x = -5

$= f(x) = {x}^{2} + 10x - 3..x = - 5$

$= f( - 5) = - 28$

= (-5, -28)

Answer 2

Answer:

A) -5, -28 is correct!

Step-by-step explanation: