Question

What is the standard form of an equation of the line going through the points K(6,4) and L(-6,4)

Answer 1

Answer:

y = 4

Step-by-step explanation:

x1 y1  x2 y2

6 4  -6 4

   

(Y2-Y1) (4)-(4)=   0  ΔY 0

(X2-X1) (-6)-(6)=    -12  ΔX -12

   

slope= 0          

B= 4          

   

Y =0X +4