Question

The Gallup Poll reported that 56% of Americans want to lose weight. If 7 people are selected at random, find the probability that they all want to lose weight. Please round the final answer to 2 or 3 decimal places.

Answer 1

Answer:

$P(7)=0.0172$

Step-by-step explanation:

From the question we are told that:

Sample size  $n = 7$

Probability of Event $P(x)=56\%$

Therefore

$P(7)=^nC_x*P^n*(1-P)^0$

$P(7)=^7C_{7}*(0.56)^7*(1-(0.56))^0$

$P(7)=0.0172$