Question

A block slides down a frictionless plane having an inclination of 15.0 degrees. The block starts from rest at the top, and the length of the incline is 2.00 m.

a) Draw a free body diagram for the block.
b) Find the acceleration of the block
c) Find its speed when it reaches the bottom of the incline.

Answer 1

Formula for the questions b and c are the following: a = g*sinΘ and V = √(2*a*d)

The following are the answers to the questions presented:

a. see attachment

b. 2.536 m/s^2 

c. 3.1852 m/s

I am hoping that these answers have satisfied your queries and it will be able to help you in your endeavors, and if you would like, feel free to ask another question.

Answer 2

Answer:

part b)

a = 2.54 m/s/s

part c)

v = 3.19 m/s

Explanation:

part b)

As we know that force due to gravity along the inclined plane is given as

$F = mgsin\theta$

acceleration of the object will be given as

$a = \frac{F}{m}$

$a = gsin\theta$

$a = 9.8 sin15 = 2.54 m/s^2$

part c)

As we know by kinematics

$v_f^2 - v_i^2 = 2 a d$

$v_f^2 - 0 = 2(2.54)(2)$

$v_f^2 = 10.16$

$v_f = 3.19 m/s$