Answer:
Step-by-step explanation:
1). Figure (1) comprises two cuboids, one small cuboid placed on the big cuboid at the bottom.
Volume of the figure = Volume of the cuboid on the top + Volume of the cuboid at the bottom
Volume of the cuboid on the top = Length × Width × Height
= 4 × 6 × 5
= 120 mm³
Volume of the cuboid at the bottom = Length × Width × Height
= 9 × 6 × 4
= 216 mm³
Volume of the figure = 120 + 216
= 336 mm³
2). Figure shown in the picture has two parts,
Cone placed on the top of a cylinder.
Volume of the given figure = Volume of cone + Volume of cylinder
= [tex]\frac{1}{3}\pi r^{2}h+\pi r^{2}h'[/tex]
= [tex]\frac{1}{3}\pi (\frac{3}{2})^{2}(3)+\pi (\frac{3}{2})^{2}(8.1)[/tex]
= [tex]\frac{9}{4}\pi +18.225\pi[/tex]
= [tex](2.25+18.225)\pi[/tex]
= [tex]20.475\pi[/tex]
= 64.3 ft³
Therefore, volume of the given figure = 64.3 ft³.
