Answer:
The volume of the pyramid is [tex]V=\frac{1}{3}(x^{2})(y)\ cm^{3}[/tex]
Step-by-step explanation:
we know that
The volume of the pyramid is equal to
[tex]V=\frac{1}{3}BH[/tex]
where
B is the area of the base
H is the height of pyramid
we know that
The area of the base is
[tex]B=x^{2}\ cm^{2}[/tex]
The height is equal to
[tex]H=y\ cm[/tex]
substitute
[tex]V=\frac{1}{3}(x^{2})(y)\ cm^{3}[/tex]