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Answer:
a) The uniform velocity travelled by the car is 10 meters per second.
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c) The distance travelled by the car with uniform velocity is 100 meters.
Explanation:
a) Calculate the uniform velocity travelled by the car:
The uniform velocity is the final velocity ([tex]v[/tex]), in meters per second, of the the uniform accelerated stage:
[tex]v = v_{o} + a\cdot t[/tex] (1)
Where:
[tex]v_{o}[/tex] - Initial velocity, in meters per second.
[tex]a[/tex] - Acceleration, in meters per square second.
[tex]t[/tex] - Time, in seconds.
If we know that [tex]v_{o} = 0\,\frac{m}{s}[/tex], [tex]a = 2\,\frac{m}{s^{2}}[/tex] and [tex]t = 5\,s[/tex], then the uniform velocity is:
[tex]v = 0\,\frac{m}{s} + \left(2\,\frac{m}{s^{2}} \right)\cdot (5\,s)[/tex]
[tex]v = 10\,\frac{m}{s}[/tex]
The uniform velocity travelled by the car is 10 meters per second.
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c) The distance travelled by the car ([tex]\Delta x[/tex]), in meters, with uniform velocity is calculated by the following kinematic expression:
[tex]\Delta x = v\cdot t[/tex] (2)
If we know that [tex]v = 10\,\frac{m}{s}[/tex] and [tex]t = 10\,s[/tex], then the distance travelled is:
[tex]\Delta x = \left(10\,\frac{m}{s} \right)\cdot (10\,s)[/tex]
[tex]\Delta x = 100\,m[/tex]
The distance travelled by the car with uniform velocity is 100 meters.