Question

hat term can you add to StartFraction 5 over 6 EndFraction x minus 4 to make it equivalent to One-half x minus 4?
Negative one-third x
Negative one-third
One-half x
One-half

Answer 1

Answer:

$\dfrac{-x}{3}$should be added to the given equation.

Step-by-step explanation:

Let a is added to the given equation.

According to the given condition,

$\dfrac{5x}{6}-4+a=\dfrac{x}{2}-4\\\\a=\dfrac{x}{2}-4+4-\dfrac{5x}{6}\\\\a=\dfrac{x}{2}-\dfrac{5x}{6}\\\\a=\dfrac{3x-5x}{6}\\\\a=\dfrac{-2x}{6}\\\\a=\dfrac{-x}{3}$

So, $\dfrac{-x}{3}$should be added to the given equation.