Answer:
[tex]\dfrac{1}{4}[/tex]
Step-by-step explanation:
The sample space of rolling a six-sided die and a coin is given below:
[tex]\left|\begin{array}{c|ccccccc}&1&2&3&4&5&6\\--&--&--&--&--&--&--\\H&H1&H2&H3&H4&H5&H6\\T&T1&T2&T3&T4&T5&T6\end{array}\right|[/tex]
Total Number of Possible Outcomes = 12, i.e. n(S)=12
Let the event of getting a head followed by an even number = A
A={H2, H4, H6}
n(A)=3
Therefore:
Probability of getting a head followed by an even number
[tex]=\dfrac{n(A)}{n(S)}\\ =\dfrac{3}{12}\\\\=\dfrac{1}{4}[/tex]