In circle C with mZBCD = 106 and BC = 6 units find area of sector BCD.
Round to the nearest hundredth.
D
с
B
![In circle C with mZBCD 106 and BC 6 units find area of sector BCD Round to the nearest hundredth D с B class=](https://us-static.z-dn.net/files/d0c/8d90eca5cdc70c322b6ce62d8765a6ce.png)
Answer:
33.30 units²
Step-by-step explanation:
Central angle = m<BCD = 106°
Radius (r) = 6 units
Area of sector BCD = central angle/360° × πr²
Plug in the values into the formula
Area of sector BCD = 106/360 × π × 6²
Area of sector BCD = 106/360 × π × 36
Area of sector BCD = 33.3008821
Area of sector BCD = 33.30 units² (nearest hundredth)