Question

A golfer hits a golf ball horizontally off an elevator tee. The ball lands in the fairy’s at 280m away. The ball is hit with an initial velocity of 52.7m/s. What is the height above the fairway of the tee?

Answer 1

Answer:

H = Vy t - 1/2 g t^2       height after time t

H = g t^2 / 2        initial Vy = 0  and take down as positive

t = S / Vx = 280 / 52,7 = 5.31 sec    time to travel horizontally

H = g / 2 * 5.31^2  = 138 m         height of tee above fairway