Question

PLEASE HELPP MEEE I HAVE 2 DAYS TO FINISH THIS CLASS AND ANOTHER

Answer 1

Step-by-step explanation:

y=x²-8x+5

0=x²-2(x)(4) +4² -4² +5

11=(x-4)²

x=4±✓11

Answer 2

Answer:

$x = 4± \sqrt{11 + y}$or $x =4 ± \sqrt{11}$

Step-by-step explanation:

Hint:

• Quadratic formula :

$\frac{ - b± \sqrt{ {b}^{2} - 4(ac)} }{2a}$

Simplify :

$y = {x}^{2} - 8x + 5$

${x}^{2} - 8x + 5 = y$

${x}^{2} - 8x + 5 - y = 0$

$\frac{8± \sqrt{( { - 8}^{2}) - 4 \times (1(5 - y) } }{2 \times 1}$

$x = \frac{8±2 \sqrt{11 + y} }{2 \times 1}$

$x = 4± \sqrt{11 + y}$

The final answer is the combination of both solutions.

$x = 4 + \sqrt{11 + y}$

$x = 4 - \sqrt{11 - y}$

Hope it is helpful....