Answer:
m = 4.58 g.
Explanation:
Hello there!
In this case, according to the given information, it turns out possible for us to realize this problem is solved via the ideal gas equation:
[tex]PV=nRT[/tex]
As we can calculate the moles of propane given the pressure, temperature and volume as shown below:
[tex]n=\frac{PV}{RT} \\\\n=\frac{1.10atm*2.00L}{0.08206\frac{atm*L}{mol*K}*258K} \\\\n=0.104mol[/tex]
Finally, since the molar mass of propane is 44.1 g/mol, we calculate the mass by following the shown below mole-mass conversion factor:
[tex]m=0.104mol*\frac{44.1g}{1mol}\\\\m= 4.58g[/tex]
Regards!
