f is inversely proportional to √ g . When f = 8 , g = 25 Work out f when g = 16
By question , f is inversely proportional to square root of g. In mathematical form ,
[tex]\implies f \propto \dfrac{1}{\sqrt g}[/tex]
Let k be constant . So that ,
[tex]\implies f =k \dfrac{1}{\sqrt g}[/tex]
When f = 8 , g is 25. So that ,
[tex]\implies 8= k\dfrac{1}{\sqrt {85}}[/tex]
[tex]\implies k = 8\sqrt{25} [/tex]
Hence the value of constant is 8√25.
So that when g is 16 ,
[tex]\implies f = 8\sqrt{25} \times 1/ \sqrt{16}\\\\\implies f = 8*5 / 4 \\\\\implies \boxed{ f = 10 } [/tex]
Hence the Value of f is 10 .