Answer: [tex]8.83\ s[/tex]
Step-by-step explanation:
Given
Height of the dropped penny is given by
[tex]h(t)=-16t^2+1250[/tex]
When penny hit the ground, [tex]h(t)=0[/tex]
[tex]\therefore -16t^2+1250=0\\\Rightarrow 16t^2=1250\\\\\Rightarrow t^2=\dfrac{1250}{16}\\\\\Rightarrow t=\sqrt{\dfrac{1250}{16}}\\\\\Rightarrow t=8.83\ s[/tex]
Thus, it takes 8.83 s to hit the ground.