Question

someone plz help and explain how you got an answer! will give brainlest
what is the equation of the line that is parallel to 3x-y=4 and goes through the point (3,2).​

Answer 1

Answer:

Step-by-step explanation:

In parallel lines gradient are the same so first re-arrange the given equation.

1. Ax+By=C

2. The equation is given in standard format $3x-y=4$

Solve for m.

1. $3x-y=4$

2. $\frac{3x}{3} =\frac{4}{3}+\frac{y}{3}$

3. $x=\frac{4}{3}+\frac{y}{3}$

Find the value of b using the formula for the equation of line.

$y=mx+b$

Substitute the value of m into the equation.

$y=(\frac{4}{3}+\frac{y}{3}) . x+b$

Substitute the value of x into the equation

$y=(\frac{4}{3}+\frac{y}{3}).(3)+b$

Substitute the value of y into the equation

$2=(\frac{4}{3}+\frac{2}{3}).(3)+b$

Find B

$b= -4$

Now we know the value of m and b. Substitute them into y=mx+b to find the equation of the line.

$y=\frac{4}{3} x+\frac{1}{3} yx-4$

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