Question

A sample of gas at 53.0 oC and 1.19 atm occupies a volume of 2.3 L. What volume would this gas occupy at 107 oC and 0.60 atm?

Answer 1

Answer:

$V_2=5.32L$

Explanation:

Hello there!

In this case, according to the given pressure, temperature and volume, it is possible for us to calculate the final volume via the combined ideal gas law:

$\frac{P_2V_2}{T_2}=\frac{P_1V_1}{T_1}$

In such a way, we solve for the final volume, V2, to obtain:

$V_2=\frac{P_1V_1T_2}{T_1P_2}$

Then, we plug in the given data to obtain:

$V_2=\frac{1.19atm*2.3L*380K}{326K*0.60atm}\\\\V_2=5.32L$

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