Question

2. If I have 7.70 moles of gas at a pressure of 202.6 kPa, and a temperature of 59.0°C, what is the
volume of the container that the gas is in?

Answer 1

Answer:

V = 0.104 m³

Explanation:

Given that,

Number of moles, n = 7.70 moles

Pressure, P = 202.6 kPa

Temperature, T = 59.0°C = 332 K

We need to find the volume of the container that the gas. We know that the ideal gas law is as follows :

$PV=nRT\\\\V=\dfrac{nRT}{P}$, R =8.314 m³-Pa/K-mol

Put all the values,

$V=\dfrac{7.7\times 8.314\times 332}{202.6 \times 10^3}\\\\V=0.104\ m^3$

So, the volume of the container is equal to 0.104 m³.