Question

A scientist prepares 500.0 L of gas at 0.921 atm pressure
and 200.0°C. The scientist transfers the gas into a tank
where it cools to 20.0°C and has a pressure of 30,0 atm.
What is the volume of the gas under these conditions?
I

Answer 1

Answer:

200.0°C.

Explanation:

Answer 2

The resulatant volume of gas under given conditions is 9.49 liters.

What is ideal gas equation?

Ideal gas equation gives idea about the behavior of gases at different conditions and it will be represented as:

PV = nRT, where

P = pressure in atm

V = volume in L

n = moles of gas

R = universal gas constant = 0.082 L.atm/K.mol

T = temperature in K

First we calculate the moles of gas by putting the values according to the first condition in the above equation and we have

n = (0.921)(500) / (0.082)(473) = 11.86 moles

Now we calculate the volume of gas by using the above equation and details of the second condition as:

V = (11.86)(0.082)(293) / (30) = 9.49 L

Hence resultant volume of the gas is 9.49L.

To know more about ideal gas equation, visit the below link:

https://brainly.com/question/555495

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