Respuesta :

[tex]S\frac{O}{H} C\frac{A}{H} T\frac{O}{A}[/tex] or [tex]Sin\frac{Opposite}{Hypotenuse}Cos\frac{Adjacent}{Hypotenuse} Tan\frac{Opposite}{Adjacent}[/tex]


At the point/angle E:

- the adjacent side(side next to the point/angle) is ED

- the opposite side(side of the triangle across from the point/angle) is DF

- the hypotenuse (the longest side of the triangle) is EF.


sin ∠E = [tex]\frac{opposite}{hypotenuse}[/tex]

sin ∠E = [tex]\frac{6}{10} = \frac{3}{5}[/tex] (simplified)

sinE = [tex]\frac{3}{5}[/tex]

the sine ratio is defined as

sin( angle ) = [tex]\frac{opposite}{hypotenuse}[/tex]

here the opposite to ∠E is 6 and the hypotenuse is 10

sinE = [tex]\frac{6}{10}[/tex] = [tex]\frac{3}{5}[/tex]


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