Question

If a team of minors drill a hole 50.4 m into a rock formation and drill at a steady rate of 2.8 m/min. how long does it take to drill the hole

Answer 1

Answer:

t = 18 minutes.

Step-by-step explanation:

We can find the time by using the following kinematic equation:

$y_{f} - y_{0} = v_{0}t + \frac{1}{2}at^{2}$  

$\Delta y = v_{0}t + \frac{1}{2}at^{2}$  

Where:  

Δy: is the difference between the initial and the final height = 50.4 m

t: is the time  

a: is the acceleration

v₀: is the velocity of the drill = 2.8 m/min

Since the speed of perforation is constant, the acceleration is zero so:

$\Delta y = v_{0}t$    

Then, by solving the above equation for "t" we have:

$t = \frac{\Delta y}{v_{0}} = \frac{50.4 m}{2.8 m/min} = 18 min$

Therefore, it takes 18 minutes to drill the hole.  

I hope it helps you!