Answer:
The correct answer is - 100 grams.
Explanation:
The solubility graph is a very useful tool because it tells you the amount of solute that can be dissolved per 100 mL of water in order to have a saturated solution of potassium nitrate at a given temperature.
In order to find the solubility of the salt at 30
∘
C
, start from the 30
∘
C
mark on the graph and move up until you intersect the curve. At the point of intersection, move left until you intersect the y axis and read off the value that you land on which is 200. However, it is for 100 ml so half the value you read:
200/2 = 100 gram
.
So, solubility ≈ 100 g / 50 mL water
So, a saturated solution of solute will hold about 100 g of dissolved solute, that is of dissociated solute, per 50 mL of water at 30
∘
C
.
