Given:
The data values are:
12, 3, 7, 8, 9, 12, 10
To find:
The mean,median ,and mode for the given set of date.
Solution:
We have,
12, 3, 7, 8, 9, 12, 10
Arrange the values in ascending order.
3, 7, 8, 9, 10, 12, 12
Mean of the data set is:
[tex]\text{Mean}=\dfrac{\text{Sum of observations}}{\text{Number of observations}}[/tex]
[tex]\text{Mean}=\dfrac{3+7+8+9+10+12+12}{7}[/tex]
[tex]\text{Mean}=\dfrac{61}{7}[/tex]
[tex]\text{Mean}\approx 8.7143[/tex]
Number of observations is 7 which is an odd number. So, the median is:
[tex]Median=\dfrac{n+1}{2}\text{th term}[/tex]
[tex]Median=\dfrac{7+1}{2}\text{th term}[/tex]
[tex]Median=\dfrac{8}{2}\text{th term}[/tex]
[tex]Median=4\text{th term}[/tex]
The 4th term from the arranged data set is 9.
[tex]Median=9[/tex]
Here, the most frequent number is 12 because it occurs 2 times. So, the mode of the data set is 12.
Therefore, the mean of the data set is 8.7143, median is 9 and mode is 12.