Derek put 10 crickets in his pet lizard’s cage. After one day, Derek’s lizard had eaten 20% of the crickets he had put in the cage. By the end of the next day, the lizard had eaten 25% of the remaining crickets. How many crickets were left in the cage at the end of the second day?

Respuesta :

Answer:

6 crickets

Step-by-step explanation:

First day:  20% of 10 is (.20)(10) = 2, so there were 10 - 2 = 8 crickets left.

Second day: 25% of 8 is (.25)(8) = 2, so there were 8 - 2 = 6 crickets left.

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