Answer:
3.29 milligrams of a metal containing 62 percent nickel must be combined with 4 mg of pure nickel to form an alloy containing 78 percent nickel.
Step-by-step explanation:
To determine how many mg of a metal containing 62 percent nickel must be combined with 4 mg of pure nickel to form an alloy containing 78 percent nickel, the following calculations must be performed:
50 + 0.62X = 78
0.62X = 78 - 50
0.62X = 28
X = 28 / 0.62
X = 45.16
100 - 45.16 = 54.84
54.84 = 4
45.16 = X
45.16 x 4 / 54.84 = X
180.64 / 54.84 = X
3.29 = X
Therefore, 3.29 milligrams of a metal containing 62 percent nickel must be combined with 4 mg of pure nickel to form an alloy containing 78 percent nickel.
