Question

On the planet Xenos, an astronaut observes that a 1.00 m long pendulum has a period of 1.50 s. What is the
free-fall acceleration on Xenos?

Answer 1

Answer:

g=1.77π2xm/s2

Explanation:

T

=

2

π

√

l

g

∴

√

l

g

=

T

2

π

∴

l

g

=

T

2

4

π

2

∴

g

l

=

4

π

2

T

2

∴

g

=

4

π

2

l

T

2

g

=

4

π

2

×

1.00

1.50

2

=

1.77

π

2

x

m/s

2