Respuesta :

Answer:

Then angles [tex]\angle B[/tex] and   [tex]\angle C[/tex] both measure [tex]55^o[/tex]

Step-by-step explanation:

Notice that if sides AB and AC are equal, then the angles opposed to them (that is angle [tex]\angle C[/tex] and angle [tex]\angle B[/tex] respectively) have to be equal since equal sides oppose equal angles in a triangle.

So you also know that the addition of the three angles in a triangle must equal [tex]180^o[/tex], then:

[tex]\angle A + \angle B+\angle C= 180^o\\70^o+\angle B + \angle B = 180^o\\2\,\angle B = 180^o-70^o\\2 \angle B=110^o\\\angle B=55^o\\\angle C = 55^o[/tex]

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