Question

A mix of factoring by grouping. Factor the exressions. 17ax+17a-x-1 Please explain/show steps on how to do this!
*edit: I know the answer to the problem because it was said aloud in a class, but I am not sure the steps to get there!

Answer 1

Answer:

$(x+1)(17a-1)$

Step-by-step explanation:

We are given that

$17ax+17a-x-1$

We have to factorize the given expression.

Pair up the terms

$(17ax+17a)+(-x-1)$

Now, taking common factor

$17a(x+1)-1(x+1)$

Taking common (x+1)

$(x+1)(17a-1)$

Now, we get

$(x+1)(17a-1)$

This is required factors of given expression.