Answer:
296.01 J
Explanation:
From the question,
Q = cm(t₂-t₁)....................... Equation 1
Where Q = quantity of heat, c = specific heat capacity of aluminium, m = mass of aluminium, t₁ = Initial temperature, t₂ = Final temperature
Given: c = 897 J/kg.K, m = 0.01 kg, t₁ = 22 K, t₂ = 55 k
Substitute these values into equation 1
Q = 897×0.01×(55-22)
Q = 897×0.01×33
Q = 296.01 J
Hence 296.01 Joules of heat is required.
