Question

2NaN3 produces 2Na+3N2 How many moles of each product are produced when 6 moles of NaN3 react?

Answer 1

Answer:

$6molNa\\\\9molN_2$

Explanation:

Hello there!

In this case, given the chemical reaction:

$2NaN_3\rightarrow 2Na+3N2$

It is possible to evidence the 2:2 mole ratio of the reactant to Na and the 2:3 mole ratio of the reactant to the N2; therefore, the following setups allows us to compute the moles of products:

$6molNaN_3*\frac{2molNa}{2molNaN_3}=6molNa\\\\6molNaN_3*\frac{3molN_2}{2molNaN_3}=9molN_2$

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